Question #6ca10

2 Answers
Jun 29, 2017

Answer:

#78" m"#.

Explanation:

Given function is

#s(t)=5t^2+t+2#

Distance covered in #t=1" s"#
#s(1)=5(1)²+(1)+2=8" m"#

Distance covered in #t=4" s"#
#s(4)=5(4)²+(4)+2=86" m"#

Distance covered in the given time interval #=86-8=78" m"#

Jun 29, 2017

Answer:

#78# #"m"#

Explanation:

We're given an equation for distance, and we're asked to find the distance traveled on the interval #t in [1color(white)(l)"s", 4color(white)(l)"s"]#.

To do this, let's find the distance covered at each of these times, and find the difference between them.

Plugging in #1# for #t#:

#s(1) = 5(1)^2 + (1) + 2 = color(red)(8# #color(red)("m"#

And then plugging in #4#:

#s(4) = 5(4)^2 + (4) + 2 = color(green)(86# #color(green)("m"#

The distance it traveled in this time interval is thus

#"Distance" = s(4) - s(1) = color(green)(86# #color(green)("m"# #- color(red)(8# #color(red)("m"# #= color(blue)(78# #color(blue)("m"#

Thus from time #t = 1# #"s"# to #t = 4# #"s"#, the object traveled a distance of #color(blue)(78# #sfcolor(blue)("meters"#.