Question #1e5b3
1 Answer
Explanation:
The first thing that you need to do here is to convert the mass of water to moles by using the compound's molar mass.
#36 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "1.998 moles H"_2"O"#
Now, you know that very mole of water contains
- two moles of hydrogen,
#2 xx "H"# - one mole of oxygen,
#1 xx "O"#
This means that your sample contains
#1.998 color(red)(cancel(color(black)("moles H"_2"O"))) * "2 moles O"/(1color(red)(cancel(color(black)("mole H"_2"O")))) = "3.996 moles O"#
Finally, to find the number of atoms of oxygen present in the sample, use the fact that
You will end up with
#3.996 color(red)(cancel(color(black)("moles O"))) * (6.022 * 10^(23)color(white)(.)"atoms O")/(1color(red)(cancel(color(black)("mole O")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(24)color(white)(.)"atoms O")))#
The answer is rounded to two sig figs.