# In one mole of glucose, how many oxygen atoms are present?

Jul 2, 2017

In glucose, ${C}_{6} {H}_{12} {O}_{6}$.....I gets $180.16 \cdot g$ of glucose.

#### Explanation:

$\text{Moles of oxygen atoms}$ $=$ $6 \times \text{moles of glucose}$. Why? Because CLEARLY, each mole of glucose, ${C}_{6} {H}_{12} {O}_{6}$ contains $6 \cdot m o l$ oxygen atoms.

Note that I am labouring the point that we deal with OXYGEN ATOMS , NOT OXYGEN MOLECULES.

$96 \cdot g$ oxygen is a molar quantity of $\frac{96 \cdot g}{16 \cdot g \cdot m o {l}^{-} 1} = 6 \cdot m o l$ with respect to oxygen atoms.

And of course if there are $6 \cdot m o l$ oxygen atoms, there must be $1 \cdot m o l$ glucose. Agreed?

We are not quite finished because we were asked for the mass, and so we multiply the molar quantity by the molar mass of glucose.....

$1 \cdot m o l \times 180.16 \cdot g \cdot m o {l}^{-} 1 = 180.16 \cdot g$.

Capisce?