# What is the concentration of pure toluene?

Jul 2, 2017

$\text{Molarity"="Moles of solute"/"Volume of solution} = 9.45 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

Now ${\rho}_{\text{toluene}} = 0.871 \cdot g \cdot m {L}^{-} 1$...and thus...

$\text{Concentration"="Moles of toluene"/"Volume of toluene}$

And we work from a $1 \cdot m L$ volume of toluene...

$\frac{\frac{0.871 \cdot g}{92.14 \cdot g \cdot m o {l}^{-} 1}}{1 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1} = 9.45 \cdot m o l \cdot {L}^{-} 1$