# Question 42152

Jul 5, 2017

$0.33$ ${\text{mol C"_6"H"_12"O}}_{6}$

#### Explanation:

We're asked to find the number of moles in $60$ $\text{g}$ glucose, ${\text{C"_6"H"_12"O}}_{6}$.

To do this, we can use the molar mass of glucose, calculated to be

$6 \left(12.01 \textcolor{w h i t e}{l} \text{g/mol") + 12(1.01color(white)(l)"g/mol") + 6(16.00color(white)(l)"g/mol}\right)$

= color(red)(180.18 color(red)("g/mol"

Using dimensional analysis, we can now convert from grams to moles:

60cancel("g glucose")((1color(white)(l)"mol glucose")/(180.18cancel("g glucose"))) = color(blue)(0.33 color(blue)("mol C"_6"H"_12"O"_6#