All you have to do here is to use Avogadro's constant and the mass of
So, you should know that, by definition, a mole of carbon must contain
#"1 mole C" = 6.022 * 10^(23)# #"atoms of C " ->#Avogadro's constant
Now, you know that the mass of
This is equivalent to saying that the mass of
Therefore, you can say that the mass of a single atom of carbon will be equal to
#1 color(red)(cancel(color(black)("atom C"))) * "12 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atom C")))) = color(darkgreen)(ul(color(black)(1.7 * 10^(-24)color(white)(.)"g")))#
The answer is rounded to two sig figs.