Question #deb43

1 Answer
Jul 7, 2017

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n) The compound is a derivative of benzene . Here 3 H atoms of benzene molecule have been replaced by 2methyl groups #(CH_3)-# and one ethyl group#C_2H_5-#. Locants on C-atoms are placed along the ring starting from one substituent in such a way that the sum of the locants on carbon atoms linked with the substituents becomes minimum. The name of the substituent/s with locant is placed in the prefix followed by the name benzene and we get the IUPAC name as

4-ethyl-1,2-dimethylbenzene

o) The compound belongs to alkene class with one #C=C#.

Its suffix name is ene

The longest C-chain selected has got 7 C-atoms .
So its stem/root name is hept

Locants on the carbon atoms of the longest carbon chain are placed in such a way that unsaturation #C=C# gets minimum locant.
3 #Br# atoms are linked with the main chain at C-atoms carrying locants 3,5.5. So the prefix name bromo is used and the complete IUPAC name will be

3,5,5-tribromohept-3-ene