# How does aluminum form a complex ion upon oxidation?

Jul 10, 2017

Well have you got $A {l}^{3 +}$ or $A l {I}_{3}$?

#### Explanation:

Aluminum does form an complex ion.........

$A {l}^{3 +} + 4 H {O}^{-} \rightarrow {\left[A l {\left(O H\right)}_{4}\right]}^{-}$

From alumina, and this is an important part in (energy-intensive) aluminum refining:

$A {l}_{2} {O}_{3} + 2 N a O H \rightarrow 2 N {a}^{+} {\left[A l {O}_{2}\right]}^{-} + {H}_{2} O$.......