# Question #dcf5f

Jul 13, 2017

Are you asking how many moles of nitrogen are need to produce $8.2 \cdot m o l$ of ammonia?
$\frac{1}{2} {N}_{2} \left(g\right) + \frac{3}{2} {H}_{2} \left(g\right) \stackrel{\text{catalysis}}{\rightarrow} N {H}_{3} \left(g\right)$
And if we make $8.2 \cdot m o l$ of ammonia, stoichiometry CLEARLY DICTATES that at least there were $4.1 \cdot m o l$ dinitrogen reactant. What is the mass of this molar quantity?