How does #H_3PO_4# behave as an acid?

1 Answer
anor277
Jul 19, 2017

Answer:

You have not quoted #K_a# values for #H_3PO_4# or #H_2PO_4^(-)#.......

Explanation:

Phosphoric acid speciates in solution according to......

#H_3PO_4(aq) + H_2O(l) stackrel(K_(a1))rightleftharpoonsH_2PO_4^(-)(aq) + H_3O^(+)#

And.............

#H_2PO_4^(-)(aq) + H_2Ostackrel(K_(a2))rightleftharpoonsHPO_4^(2-)(aq) + H_3O^(+)#

We need #K_(a1)# and #K_(a2)# before we can address your question.

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