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Answer 1 · 2017-07-28T23:16:55

There are #3.6 × 10^21 color(white)(l)"atoms of Fe"# in 100 g of hemoglobin.

Step 1. Calculate the mass of #"Fe"#

#"Mass of Fe" = 100 color(red)(cancel(color(black)("g Hb"))) × "0.33 g Fe"/(100 color(red)(cancel(color(black)("g Hb")))) = "0.33 g Fe"#

Step 2. Calculate the moles of #"Fe"#

#"Moles of Fe" = 0.33 color(red)(cancel(color(black)("g Fe"))) × "1 mol Fe"/(55.85 color(red)(cancel(color(black)("g Fe")))) = "0.005 91 mol Fe"#

Step 3. Calculate the atoms of #"Fe"#

#"Atoms of Fe" = "0.005 91" color(red)(cancel(color(black)("mol Fe"))) × (6.022 × 10^23 "atoms Fe")/(1 color(red)(cancel(color(black)("mol Fe")))#

# = 3.6 × 10^21 color(white)(l)"atoms Fe"#