Question

How much dihydrogen would evolve if sodium metal were dropped into water?

Answer 1

You need to specify a mass of sodium metal.......

`Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr`

Explanation:

If `1*g` of sodium metal were dropped into a beaker of water, along with spitz and sparx we would get......

`1/2xx(1*g)/(22.99*g*mol^-1)xx2.02*g*mol^-1=0.044*g` `"dihydrogen gas"`.

Of course, if we specify the temperature, and assume `1*atm` pressure, we could calculate the volume of dihydrogen gas produced.