# Question #7d366

Jul 19, 2017

$C = 0.01175 M$

#### Explanation:

Let's first find how many mols are $2.35 g r a m s$ of $N a O H$

${n}_{\text{NaOH}} = \frac{m}{M r} = \frac{2.35}{40} = 0.05875 m o l s$

Let's now convert the $500 c {m}^{3}$ into $L i t r e s$

$500 c {m}^{3} = 500 c {m}^{3} \cdot \frac{0.001 L}{1 c {m}^{3}} = 5 L$

Now the concentration is:

$C = \frac{n}{V} = \frac{0.05875}{5} = 0.01175 M$