Question #99452

1 Answer
Jul 20, 2017

Answer:

17 %

Explanation:

Start with the equation:

#sf(CaCO_(3(s))rarrCaO_((s))+CO_(2(g)))#

This tells us that:

1 mole #rarr# 1 mole + 1mole

Convert moles to grams #rArr#

100g #rarr#56g + 44g

#:.# 10g#rarr#5.6g + 4.4g

This means that 12g of the impure sample must contain 10g of #sf(CaCO_3)# and 2g of impurity.

#:.#% impurity = #sf((2)/12xx100=17)#