Question #c376a

1 Answer
Jul 22, 2017

Answer:

5.64g

Explanation:

34g of #text(H)_2text(S)# contains #6.022×10^23# molecules of #text(H)_2text(S)#

Mass of #1.0×10^23# molecules of #text(H)_2text(S)# is = #(1.0×10^23×34)/(6.022×10^23)# = #5.64g#