Question

What is `"volume percent"` of a `10*g` mass of solute dissolved in a `150*g` mass of solvent?

Answer 1

Are you sure you mean to specify `"volume percent"`?

Explanation:

Normally we reserve the term for the concentration.......

`"Volume of solute"/"Volume of solution"xx100%`

And we have no handle on the volume of solute here........as it is commonly used for gas/gas or liquid/liquid solutions.

We could more properly quote concentration in terms of......

`"Mass of solute"/"Mass of solute + mass of solvent"xx100%`

`(10*g)/(10*g+150*g)xx100%=6.25%("m/m")`.

WE could of course quote concentration in more familiar terms as..

`"molarity"="Moles of solute"/"Volume of solution (L)"`.

And since, at these concentrations, volume change on dissolution would be negligible, we write........

`((10*g)/(101.10*g*mol^-1))/(150*gxx1*mL*g^-1*10^-3L*mL^-1)=0.659*mol*L^-1.`