Question #5991c

Question

1143 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-23T06:22:01

a. #"Number of molecules" = "Avogradro's contant"*"Number of moles"#

#0.45(6.02*10^(23))=2.709*10^(23)~~2.71*10^(23)#

b. #"Number of atoms" = "Number of molecules"*"Number of atoms in one molecule"#

#NH_4Cl# = 6 atoms

#6(2.709*10^(23))=1.6254*10^(24)~~1.63*10^(24)#

c. #"Number of atoms in 1 mole"="Avogadro's constant"*"Number of atoms in one molecule"#

#6(6.02*10^(23))=3.612*10^(24)~~3.61*10^(24)#

d. #"Number of atoms of one element"="Number of molecules"*"Number of atoms of one element in one molecule"#

#4(2.709*10^(23))=1.0836*10^(24)~~1.08*10^(24)#

d. #n(NH_4Cl) = 0.45mol#
#n(H_4)# in #NH_4Cl = 0.45*4/53.5=0.0336448598~~3.36*10^(-2)mol#