What is the empirical formula of a species that is #7.19%# by mass with respect to phosphorus, and #92.81%# by mass with respect to bromine? What is the molecular formula is the molecular mass is #431*g*mol^-1#?
And this gives (i) microanalysis of
For these data we determine the empirical formula......by assuming an
In each case I divided the elemental mass thru by the molar mass of the ELEMENT.
We divide thru by the lowest molar quantity (that of
Now, we know that.........