Question

Question #e7184

Answer 1

On average, the pressure dropped by 0.83 bar each day.

Explanation:

From the Ideal Gas Law, you know that

`pV = nRT`

Thus,

`p ∝ n`.

The number of moles, `n`, is directly proportional to the mass `m` of the gas, so

`p ∝ m`.

This means that, if the mass decreases by a certain factor, the pressure will decrease by the same factor.

Here, the mass has decreased to 10 kg from 15 kg, a factor of `10/15`.

The pressure will decrease by the same factor.

Hence, the new pressure will be

`"10 bar" × 10/15 = "6.67 bar"`

The drop in pressure is

`"10 bar - 6.67 bar = 3.33 bar"`

This pressure drop occurred over four days.

∴ The average pressure drop per day was

`"3.33 bar"/"4 days" = "0.83 bar/day"`