Question #e7184

1 Answer
Jul 25, 2017

Answer:

On average, the pressure dropped by 0.83 bar each day.

Explanation:

From the Ideal Gas Law, you know that

#pV = nRT#

Thus,

#p ∝ n#.

The number of moles, #n#, is directly proportional to the mass #m# of the gas, so

#p ∝ m#.

This means that, if the mass decreases by a certain factor, the pressure will decrease by the same factor.

Here, the mass has decreased to 10 kg from 15 kg, a factor of #10/15#.

The pressure will decrease by the same factor.

Hence, the new pressure will be

#"10 bar" × 10/15 = "6.67 bar"#

The drop in pressure is

#"10 bar - 6.67 bar = 3.33 bar"#

This pressure drop occurred over four days.

∴ The average pressure drop per day was

#"3.33 bar"/"4 days" = "0.83 bar/day"#