# How is a 35% "w/w" solution of a 200*g mass of sodium chloride in water prepared?

##### 1 Answer
Jul 25, 2017

About $70 \cdot g$ of salt, and $130 \cdot m L$ water.........

#### Explanation:

"Concentration"="Mass of solute"/"Mass of solute + mass of water"xx100%

And thus 35%="Mass of solute"/(200*g)....

And so "mass of solute"-=35%xx200*g=70*g.

And the volume of the solution would change only very marginally, even upon the addition of such a mass of solute.