Question #47cde

1 Answer
Jul 25, 2017

Well there are #1.5*molxxN_A........# carbon atoms.......

Explanation:

Where #N_A-="Avogadro's Number"-=6.022xx10^23*mol^-1#

So we gots #1.5*cancel(mol)xx6.022xx10^23*cancel(mol^-1)~=9xx10^23*# #"carbon atoms"#.

What is the mass of this quantity of carbon atoms?