# What is the molarity of "50% w/w" HCl solution for which rho_"solution"=1.15*g*cm^-3?

Jul 27, 2017

You have not specified a solvent.......and the question has not been written by a chemist......

#### Explanation:

We assume an aqueous solution of hydrochloric acid, and clearly a $1 \cdot m L$ volume of the stuff contains 50%xx1*cm^3xx1.15*g*cm^-3=0.575*g $H C l$.....

And thus the concentration is.......$\text{moles of solute"/"volume of solution}$

((50%xx1*cm^3xx1.15*g*cm^-3)/(36.46*g*mol^-1))/(1xx10^-3*L)-=15.8*mol*L^-1.

The most concentrated hydrochloric acid you can buy is 36-38%(w/w); typically we are supplied conc. $H C l$ as a $10.5 \cdot m o l \cdot {L}^{-} 1$ solution in the laboratory.