Question

Question #ae174

Answer 1

Always Quadratic

Explanation:

Let `f(x) = ax^2 + bx + c` (with `a ne 0`),
and let `g(x) = dx + e`.

Then `(f+g)(x) = ax^2 + (b + d)x + (c + e)`.
Since `a ne 0`, this is quadratic every time.