Question #7c768

1 Answer
Jul 31, 2017

Answer:

#0.227# #"mol CO"_2#

Explanation:

We're asked to find the number of moles of #"CO"_2# in #10.0# #"g CO"_2#.

To do this, we need to find the molar mass of #"CO"_2#, which is

#overbrace((1))^"1 carbon atom"overbrace((12.011color(white)(l)"g/mol"))^" molar mass of carbon" + overbrace((2))^"2 oxygen atoms"overbrace((15.999color(white)(l)"g/mol"))^" molar mass of oxygen"#

#= color(red)(44.01color(white)(l)"g/mol"#

(the molar masses of each element can be found on a periodic table or online).

Now, we use dimensional analysis to convert from grams to moles:

#10.0cancel("g CO"_2)((1color(white)(l)"mol CO"_2)/(color(red)(44.01)cancel(color(red)("g CO"_2)))) = color(blue)(ul(0.227color(white)(l)"mol CO"_2#