# Question 7c768

Jul 31, 2017

$0.227$ ${\text{mol CO}}_{2}$

#### Explanation:

We're asked to find the number of moles of ${\text{CO}}_{2}$ in $10.0$ ${\text{g CO}}_{2}$.

To do this, we need to find the molar mass of ${\text{CO}}_{2}$, which is

${\overbrace{\left(1\right)}}^{\text{1 carbon atom"overbrace((12.011color(white)(l)"g/mol"))^" molar mass of carbon" + overbrace((2))^"2 oxygen atoms"overbrace((15.999color(white)(l)"g/mol"))^" molar mass of oxygen}}$

= color(red)(44.01color(white)(l)"g/mol"

(the molar masses of each element can be found on a periodic table or online).

Now, we use dimensional analysis to convert from grams to moles:

10.0cancel("g CO"_2)((1color(white)(l)"mol CO"_2)/(color(red)(44.01)cancel(color(red)("g CO"_2)))) = color(blue)(ul(0.227color(white)(l)"mol CO"_2#