Which quantity contains the LEAST number of atoms?

$a .$ $\text{Two moles of NaOH;}$ $b .$ $\text{One mole of ammonia; }$ $c .$ $\text{Two moles of calcium chloride; }$ $d .$ $\text{One mole of alumina. }$

Aug 2, 2017

I would go for $\text{option b}$.

Explanation:

You gots.......

$a .$ $\text{Two moles of NaOH;}$ $2 \times N {a}^{+} + 2 H {O}^{-}$ $\text{moles}$

$b .$ $\text{One mole of ammonium; }$ $1 \times N {H}_{3} \cdot m o l$

$c .$ $\text{Two moles of calcium chloride; }$ $2 \times C {a}^{2 +} + 4 \times C {l}^{-} \cdot m o l$

$d .$ $\text{One mole of alumina; }$ $2 \times A {l}^{3 +} + 3 \times {O}^{2 -} \cdot m o l$

Is this clear?