Question #1bf5d

2 Answers
Aug 3, 2017

Answer:

#"displacement" = 230# #"m"#

Explanation:

We're asked to find the displacement of a car after a certain time, given its constant acceleration.

To do this, we can use the kinematics equation

#ul(Deltax = v_(0x)t + 1/2a_xt^2#

Since the car started from rest, the initial velocity #v_(0x)# is zero, leaving us with

#ul(Deltax = 1/2a_xt^2#

where

  • #Deltax# is the change in position (displacement, which is what we're trying to find)

  • #a_x# is the constant acceleration (given as #2.0# #"m/s"^2#)

  • #t# is the time interval (given as #15# #"s"#)

Plugging in known values, we have

#Deltax = 1/2(2.0color(white)(l)"m/s"^2)(15color(white)(l)"s")^2 = color(red)(ulbar(|stackrel(" ")(" "230color(white)(l)"m"" ")|)#

rounded to #2# significant figures.

Answer:

The displacement is #"225 m"#.

Explanation:

![https://d2jmvrsizmvf4x.cloudfront.net/N05GPlprT0yAjHzylKE4_15017753773091702346355.jpg)