Question #1bf5d
2 Answers
Answer:
Explanation:
We're asked to find the displacement of a car after a certain time, given its constant acceleration.
To do this, we can use the kinematics equation
#ul(Deltax = v_(0x)t + 1/2a_xt^2#
Since the car started from rest, the initial velocity
#ul(Deltax = 1/2a_xt^2#
where

#Deltax# is the change in position (displacement, which is what we're trying to find) 
#a_x# is the constant acceleration (given as#2.0# #"m/s"^2# ) 
#t# is the time interval (given as#15# #"s"# )
Plugging in known values, we have
#Deltax = 1/2(2.0color(white)(l)"m/s"^2)(15color(white)(l)"s")^2 = color(red)(ulbar(stackrel(" ")(" "230color(white)(l)"m"" "))#
rounded to
Answer:
The displacement is
Explanation:
![https://d2jmvrsizmvf4x.cloudfront.net/N05GPlprT0yAjHzylKE4_15017753773091702346355.jpg)