# Question 1bf5d

Aug 3, 2017

$\text{displacement} = 230$ $\text{m}$

#### Explanation:

We're asked to find the displacement of a car after a certain time, given its constant acceleration.

To do this, we can use the kinematics equation

ul(Deltax = v_(0x)t + 1/2a_xt^2

Since the car started from rest, the initial velocity ${v}_{0 x}$ is zero, leaving us with

ul(Deltax = 1/2a_xt^2

where

• $\Delta x$ is the change in position (displacement, which is what we're trying to find)

• ${a}_{x}$ is the constant acceleration (given as $2.0$ ${\text{m/s}}^{2}$)

• $t$ is the time interval (given as $15$ $\text{s}$)

Plugging in known values, we have

Deltax = 1/2(2.0color(white)(l)"m/s"^2)(15color(white)(l)"s")^2 = color(red)(ulbar(|stackrel(" ")(" "230color(white)(l)"m"" ")|)#

rounded to $2$ significant figures.

Aug 3, 2017

The displacement is $\text{225 m}$.