Question #86eb9

1 Answer
Aug 4, 2017

Answer:

All hydrocarbons combust to give carbon dioxide and water.......

Explanation:

#C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)#

#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(l)#

And if combust a #40*g# mass of propane......you gets.....

#(40*g)/(44.1*g*mol^-1)xx3xx44.01*g*mol^-1=119.8*g*CO_2#

And if combust a #60*g# mass of butane......you gets.....

#(60*g)/(58.12*g*mol^-1)xx4xx44.01*g*mol^-1=181.7*g*CO_2#