# Question #51efc

${\text{NHF}}_{2}$ has $\textcolor{red}{7}$ lone pairs of electrons, $3$ single bonds, and nitrogen has a usual octet. You seem to have counted the three single bonds as additional lone pairs.
${\text{NHF}}_{2}$ is analogous to ${\text{NH}}_{3}$, with two hydrogen atoms replaced by fluorine atoms.
Three lone pairs per fluorine atom gives $6$, plus the lone pair on nitrogen gives $7$. $\text{N}$ atom has the usual octet; two electrons from each single bond and two from the lone pair.