Question #32f0e

1 Answer
Aug 19, 2017

x=0

Explanation:

Let's simplify the radicals.

\sqrt(60)=\sqrt(2^2*15)=2\sqrt(15)

\sqrt(15)=\sqrt(15)

\sqrt(135)=\sqrt(3^2*15)=3\sqrt(15)

Now, we know that if two radicals have the same value underneath the square root, we can combine them, like so:

a\sqrt(b)-csqrt(b)=(a-c)sqrt(b)

So,

2\sqrt(15)+sqrt(15)-3sqrt(15)=3sqrt(15)-3sqrt(15)=0

Thus,

0=\sqrt(x) so x=0.