Question #32f0e

1 Answer
Aug 19, 2017

Answer:

#x=0#

Explanation:

Let's simplify the radicals.

#\sqrt(60)=\sqrt(2^2*15)=2\sqrt(15)#

#\sqrt(15)=\sqrt(15)#

#\sqrt(135)=\sqrt(3^2*15)=3\sqrt(15)#

Now, we know that if two radicals have the same value underneath the square root, we can combine them, like so:

#a\sqrt(b)-csqrt(b)=(a-c)sqrt(b)#

So,

#2\sqrt(15)+sqrt(15)-3sqrt(15)=3sqrt(15)-3sqrt(15)=0#

Thus,

#0=\sqrt(x)# so #x=0#.