Question #56801

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Answer 1 · 2017-08-20T02:36:26

# sin(2tan^-1 (2/3))+cos(tan^-1√3)#

#= (2xx2/3)/(1+(2/3)^2)+cos(sec^-1sqrt(1+(√3)^2))#

#= (4/3)/(13/9)+cos(sec^-1 2)#

#=12/13+coscos^-1(1 /2)#

#=12/13+1/2#

#=24/26+13/26#

#=37/26#