Question

Question #47c1a

Answer 1

`RHS=(cottheta -1)/ (2-sec^2 theta)`

`=(1/tantheta -1)/ (2-(1+tan^2 theta)`

`=((1-tantheta )/tantheta)/ (1-tan^2 theta)`

`=(cottheta(1-tantheta ))/( (1-tan theta)(1+tantheta)`

`=cot theta /( 1 + tan theta) =LHS`