Question #fc45c

1 Answer
Aug 21, 2017

Answer:

#"0.133 moles"#

Explanation:

The idea here is that you need to use the molar mass of sucrose to calculate the number of moles present in your sample.

You know that sucrose has a molar mass of #"342.3 g mol"^(-1)#, which means that #1# mole of sucrose has a mass of #"342.3 g"#.

You want to go from grams to moles, so set up the molar mass of the substance as a conversion factor that has moles in the numerator and grams in the denominator.

https://www.boundless.com/chemistry/textbooks/boundless-chemistry-textbook/mass-relationships-and-chemical-equations-3

You should end up with

#45.4 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.3 color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("0.133 moles sucrose")))#

The answer is rounded to three sig figs.