Question

Question #fc45c

Answer 1

`"0.133 moles"`

Explanation:

The idea here is that you need to use the molar mass of sucrose to calculate the number of moles present in your sample.

You know that sucrose has a molar mass of `"342.3 g mol"^(-1)`, which means that `1` mole of sucrose has a mass of `"342.3 g"`.

You want to go from grams to moles, so set up the molar mass of the substance as a conversion factor that has moles in the numerator and grams in the denominator.

You should end up with

`45.4 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.3 color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("0.133 moles sucrose")))`

The answer is rounded to three sig figs.