What is the square root of #-64# ?

1 Answer
Aug 23, 2017

The square roots of #-64# are #8i# and #-8i# where #i# is the imaginary unit, satisfying #i^2 = -1#.

Explanation:

The square of any Real number is non-negative, so to find a square root for #-64# we need to look beyond the Real number line to Complex numbers.

The imaginary unit #i# is a number whose square is #-1#. So it is a square root of #-1#.

Note that #-i# is also a square root of #-1#, satisfying #(-i)^2 = i^2 = -1#

For any negative number #n# we find:

#(isqrt(-n))^2 = i^2(-n) = (-1)(-n) = n#

So #isqrt(-n)# is a square root of #n#. By convention, this is the principal square root and therefore the one we mean by #sqrt(n)#.

In our particular example:

#sqrt(-64) = isqrt(64) = isqrt(8^2) = 8i#