# What is the mass in grams of "CaCl"_2" in a "3 M CaCl"_2" solution?

$\text{300 g CaCl"_2}$
"Molarity"=("mol solute")/("liter of solution")
A 3 M solution of calcium chloride contains 3 moles of the solute ${\text{CaCl}}_{2}$ in one liter of solution. To convert 3 mol ${\text{CaCl}}_{2}$ to mass in grams, multiply the given moles by the molar mass: $\text{110.978 g/mol}$.
3color(red)cancel(color(black)("mol CaCl"_2))xx(110.978"g CaCl"_2)/(1color(red)cancel(color(black)("mol CaCl"_2)))="300 g CaCl"_2" (rounded to one significant figure due to 3 mol)