Question #57531
1 Answer
Nov 28, 2017
(D) is optically active.
Explanation:
(A)
(A) is not optically active because there are no chiral carbons. There is an internal plane of symmetry.
(B)
(B) is not optically active because there are no chiral carbons. There is an internal plane of symmetry.
(C)
(C) is not optically active because there are no chiral carbons. There is an internal plane of symmetry.
(D)
(D) is optically active because there are two chiral carbons and no internal plane of symmetry.
