Question

If the area of the base of a square pyramid is `169 ft^2`, what is the perimeter of the base?

Answer 1

`p = 52" ft"`

Explanation:

The area of the square base is:

`s^2 = 169" ft"^2`

where `s` is the length of the 4 equal sides.

Solve for s:

`s = sqrt169`

`s = 13" ft"`

The formula for the perimeter is:

`p = 4s`

`p = 4(13" ft")`

`p = 52" ft"`

Answer 2

`P=52"ft"`

Explanation:

If the area of the base of the pyramid is `169"ft"^2` then each side of the base is `13"ft"` long because the base of the pyramid is a square.

Length of the side, `s= sqrt169 = 13`

Iif we take the area of a square `A=s^2` where `s=13` we get the area of the base to be `169"ft"^2` thus proving that each side of the base is `13"ft"` long.

So to find the perimeter of the base of the pyramid we use the formula:

`P=4s` where `s=13"ft"` and thus,

`p=4*13"ft"=52"ft"`