# A, whose formula is C_6H_12, and which contains a chiral centre, is oxidized by permanganate ion to give methane gas, and "2-methylbutanoic acid". What is A?

Aug 27, 2017

I think you gots $\text{3-methylpentene}$.......

#### Explanation:

$\text{3-methylpentene}$.......fits the description for $A$.

${H}_{3} \stackrel{5}{C} - C {H}_{2} - \stackrel{3}{C} H \left(C {H}_{3}\right) \stackrel{2}{C} = \stackrel{1}{C} {H}_{2}$

We start with an olefin.......${H}_{2} C = C H C H \left(C {H}_{3}\right) C {H}_{2} C {H}_{3}$, with a chiral centre at $C 3$.

And hot permanganate will oxidize off the methylene group as carbon dioxide to give......

${H}_{3} \stackrel{4}{C} - C {H}_{2} - \stackrel{2}{C} H \left(C {H}_{3}\right) C {O}_{2} H$

We have a carboxyl group at the position of the former ${C}_{2}$.

The chiral centre is the prior $C 3$.