Question #12f02
1 Answer
Explanation:
The key here is the fact that
#color(blue)(ul(color(black)("1 Gs" = 10^9color(white)(.)"s")))#
This means that you need
This means that
#"1 Gs" xx "1 Gs" = 10^9color(white)(.)"s" xx 10^9color(white)(.)"s"#
#color(blue)(ul(color(black)("1 Gs"^2 = 10^18color(white)(.)"s"^2)))#
In your case, you have
#1.3 * 10^5color(red)(cancel(color(black)("Gs"^2))) * (10^18color(white)(.)"s"^2)/(1color(red)(cancel(color(black)("Gs"^2)))) = color(darkgreen)(ul(color(black)(1.3 * 10^(23)color(white)(.)"s"^2)))#
The answer is rounded to two sig figs, the number of sig figs you have for the number of gigaseconds squared.