# What is the average atomic mass of titanium if we have an isotopic distribution of 78.5% of ""^46Ti, 45.95263*"amu", 12.3% of ""^48Ti, 47.94795*"amu", and ""^50Ti, 49.94479*"amu"?

This is simply the WEIGHTED AVERAGE of the individual isotopes.....I gets approx. $46.6 \cdot \text{amu}$.
"Atomic mass of titanium"={0.785xx45.95263+0.123xx47.94795+0.092xx49.94479}*"amu"=??