# Question #082ad

##### 1 Answer

Aug 31, 2017

#### Explanation:

Condense the logarithms using the rules:

#log(A^B)=Blog(A)# #log(A)-log(B)=log(A/B)#

Then

#ln(x-3)-ln(3^2)=2#

#ln((x-3)/3^2)=2#

Rewrite by exponentiating both sides with base

#(x-3)/9=e^2#

From here, solving for

#x=9e^2+3#