Question #3dd5d

1 Answer
Michael
Aug 31, 2017

#sf(pH=3)#

Explanation:

The acid dissociates:

#sf(HZrightleftharpoonsH^++Z^-)#

Since it is 1% ionised then #sf([H^+]=0.10xx0.01=0.001color(white)(x)"mol/l")#

#sf(pH=-log[H^+]=-log(10^(-3))=3)#

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