# Question 0c3b7

Sep 2, 2017

Here's what I got.

#### Explanation:

The idea here is that you need to use the known composition of the glucose solution to determine how many grams of glucose are present in $\text{3.1 L}$ of this solution.

So, you know that

$\text{1 L} = {10}^{3}$ $\text{mL}$

and that $\text{100. mL}$ of this glucose solution contain $\text{5.9 g}$ of glucose. To find the mass of glucose present in $\text{3.1 L}$ of glucose solution, convert the volume of the solution from liters to milliliters and set up the known composition as a conversion factor.

3.1 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "5.9 g glucose"/(100. color(red)(cancel(color(black)("mL solution")))) = "183 g glucose"#

Now, the problem should provide you with the number of calories or kilocalories released per gram of glucose.

Assuming that $\text{1 g}$ of glucose releases $\text{3.811 kcal}$ of energy when digested, you can say that the patient received a total of

$183 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{g glucose"))) * "3.811 kcal"/(1color(red)(cancel(color(black)("g glucose")))) = color(darkgreen)(ul(color(black)(7.0 * 10^2color(white)(.)"kcal}}}}$

The answer is rounded to two sig figs.