# Question #318cb

Sep 1, 2017

$\text{1 mole}$ of stuff specifies $6.02214 \times {10}^{23}$ individual items of that stuff..........

#### Explanation:

And so $\text{1 mole}$ of lithium specifies $6.02214 \times {10}^{23}$ individual lithium atoms, and this has a mass of $6.94 \cdot g$; i.e. we quote the equivalent mass of lithium metal as $6.94 \cdot g \cdot m o {l}^{-} 1$. This concept of equivalence is one of the most important to grasp in chemistry.

For the reaction......

$2 L i \left(s\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow L {i}_{2} O$

If approx. $14 \cdot g$ of lithium reacts, how many oxygen molecules react, how many formula units of lithium oxide result, and what is the mass of lithium oxide?