# Question #d6ec5

##### 1 Answer

The distribution is *not* symmetric, centered at about 2-3, has a spread from 0-8 servings, and has no outliers. Percentages are below.

#### Explanation:

If you look at the left half of the graph and the right half of the graph, they don't look the same, so it is not symmetric.

The data looks like there are:

- 15 girls who ate 0 servings
- 11 girls who ate 1 serving
- 15 girls who ate 2 servings
- 11 who ate 3 servings
- 8 who ate 4 servings
- 5 who ate 5 servings
- 3 who ate each 6, 7, and 8 servings

Therefore, the number of girls involved in the study *does* add up to 74, and the middle, or *median* value is the 37th value from either end. If you were to write out the data, with fifteen *mean*, value is about

We say the data is skewed right because the graph has a "tail" going to the right. Google "skew of data" to see more examples.

The spread is the range whatever you're measuring, so here your spread is 0-8 pieces of fruit.

There are no outliers because all the data on the graph is grouped together. If there were some people, for example, who ate 19 pieces of fruit, that would be an outlier. Outliers are significant primarily because they affect the way our measures look. While they likely do not affect the median so much, they significantly change the mean value.

Percentages:

What percent ate 7 or more servings? Six of the girls ate 7 or more servings, and

For the percent who ate fewer than 3 servings, include

- 15 girls who ate 0 servings

- 11 girls who ate 1 serving

- 15 girls who ate 2 servings

...which is 41 of the participants.