Question

Question #a9c80

Answer 1

From this data, we can say there is liquid present, approximately `5.2g`.

Explanation:

This is a pretty complex gas law question.

The vapor pressure of a liquid is when liquid and gas phase transition are in equilibrium.

For the purposes of this question I've converted your pressure atm:

`P = 1.138` atm

`1.138atm*1.0L = n*(0.08026L*atm)/(mol*K)*300K`

`therefore n approx 4.6*10^-2mol`

`MM[C Cl_3F] = (137.5g)/(mol)`

`4.6*10^-2mol* (137.5g)/(mol) approx 6.325g` of trichloroflouromethane gas.

Subtract the mass of the gas present from the mass of the liquid...