# Question #ca53b

Sep 4, 2017

Approximately $8.82 \cdot {10}^{-} 3 m o l$ or $1.72 g$ of platinum.

#### Explanation:

This is a very vague question, but I will assume you're looking for how much they weigh.

$\left(5.31 \cdot {10}^{21} m o l .\right) \cdot \frac{m o l}{6.023 \cdot {10}^{23} m o l .} \approx 8.82 \cdot {10}^{-} 3 m o l$

Note that mol. is referring to molecules and mol (without the period) is referring to moles.

$8.82 \cdot {10}^{-} 3 m o l \cdot \frac{195.1 g}{m o l} = 1.72 g$