# What are the molar and molal concentrations of a 9.27*g mass of sodium chloride dissolved in 30*mL of water?

Sep 6, 2017

Well, we can work out the $\text{molality}$.

#### Explanation:

$\text{Molality"="Moles of solute"/"Kilograms of solvent}$

$= \frac{\frac{9.27 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1}}{30 \cdot g \times {10}^{-} 3 \cdot g \cdot k {g}^{-} 1} = 5.29 \cdot m o l \cdot k g$...

On the other hand....

$\text{Molarity"="Moles of solute"/"Litres of solution}$

We expect the molarity to be near as dammit to the molality, even for this concentrated solution.....given that in this instance, volume of solution would be relatively unchanged with respect to the pure solvent.