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Question #e96d5

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Answer:

#0.932 xx 10^(-5)#

Explanation:

It's so easy to understand.

The only thing we have to know is that 1 mol of any gas has a volume of 24.04 L at NTP (Normal Temperature and Pressure)

Here the volume is given as 2.24 mL.

                     1 L = 1000 mL

Hence #"1 mL" = 10^(-3) " L"#

#"2.24 mL" = 2.24 xx 10^(-3) " L"#

#"24.04 L of CO"_2 = "1 mol of CO"_2# (at NTP only)

#2.24 xx 10^(-3) " L CO"_2 xx ("1 mol CO"_2)/("24.04 L CO"_2) = 9.32 xx 10^(-5) " mol CO"_2#

Therefore 2.24 mL #"CO"_2# at NTP contains #0.932 xx 10^(-5) " mol CO"_2#.

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