Question #1e5b9
1 Answer
Relative velocity of projectile w.r.t plane=Actual velocity of projectile-velocity of plane
So,Actual velocity of projectile=
Let's,consider that the projectile will touch the ground after time t,
So with in this time,along X axis if it travels a distance of s from its point of projection,we can say
And along Y axis,
Vertical height of plane above the ground = 800 =
Eliminating t from both the equations we get,
800 =
Or, s= 5551.56 meters
So at that time along x axis its velocity will be 438.89 m/sec
Along Y axis we can find it using equation
So,v= 126.5 m/sec
Hence net velocity with which it will hit the ground will be
Or, 456.75 m/sec