# If a binary metal halide whose %Cl is 60.68%, what is the likely salt?

Sep 8, 2017

We are given $M C l$, where chloride content is 60.68% by mass....we gots sodium metal.....

#### Explanation:

So we solve for the atomic mass of $M$.....

60.68%=(35.5*g)/("Formula mass of salt, g")xx100%

$\text{Formula mass of salt} = \frac{35.5 \cdot g}{0.6068} = 58.5 \cdot g$

But because there is ONE CHLORIDE, we know that the formula mass of the metal is.....

${M}_{\text{mass}} = \left(58.5 - 35.45\right) \cdot g = 23.0 \cdot g$

And a quick glance at the Periodic Table tells us that the metal is likely to be sodium, i.e. $22.99 \cdot g \cdot m o {l}^{-} 1$.

Capisce?