If a binary metal halide whose #%Cl# is #60.68%#, what is the likely salt?

1 Answer
Sep 8, 2017

Answer:

We are given #MCl#, where chloride content is #60.68%# by mass....we gots sodium metal.....

Explanation:

So we solve for the atomic mass of #M#.....

#60.68%=(35.5*g)/("Formula mass of salt, g")xx100%#

#"Formula mass of salt"=(35.5*g)/(0.6068)=58.5*g#

But because there is ONE CHLORIDE, we know that the formula mass of the metal is.....

#M_"mass"=(58.5-35.45)*g=23.0*g#

And a quick glance at the Periodic Table tells us that the metal is likely to be sodium, i.e. #22.99*g*mol^-1#.

Capisce?